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渗透之Python学习(str字符串)
感谢大家的关注,小编我今天又要挖一个坑啦,分享Python的学习笔记。
都说网络安全这条路,python语言是必学的。为什么呢?因为一旦网上爆出某个漏洞,你得会用Python去编写EXP利用它呀。这样可以避免没必要的人力,直接脚本检测就ok啦。如果你对这个没有详细的概念,可以看我前面的那篇redis获取服务器权限的文章。只要运行脚本,就可以直接代替人省略了十多步操作,直接获取权限,是不是很方便呢。
从现在起我会不间断的分享我的Python学习笔记,供大家学习。
因为篇幅字数有限,没有办法把所有的笔记都放在这里。有兴趣的读者可以私聊我或者加群:928233686领取我的所有笔记。
下图是我要不断分享的Python模块笔记,附带源码解释,中文翻译和各种实例,让你对该模块有更深入的理解。
# capitalize() 将第一个字母大写 ''' capitalize(...) S.capitalize() -> str Return a capitalized version of S, i.e. make the first character have upper case and the rest lower case. ''' #print(help(str.capitalize)) a = 'asdffghjkl' b = a.capitalize() print(b) # b = Asdffghjkl ------------------------------------------------------------------------------------------- # casefold() 返回小写,与lower()类似,但lower只针对ASCII,casefold()针对Unicode() ''' casefold(...) S.casefold() -> str Return a version of S suitable for caseless comparisons. ''' print(help(str.casefold)) a = 'ASD' b = a.casefold() print(b) # b = asd ------------------------------------------------------------------------------------------- # 用指定的宽度来返回一个居中版的s, # 如果需要的话,就用fillchar进行填充,默认是空格。但是不会对s进行截取。 # 即如果s的长度比width大,也不会对s进行截取。 ''' center(...) S.center(width[, fillchar]) -> str Return S centered in a string of length width. Padding is done using the specified fill character (default is a space) ''' print(help(str.center)) a = 'asdfghjkl' b = a.center(20, '-') # 长度为20,a字符串居中,左右用数字5填充 print(b) # b = 55555asdfghjkl555555 ------------------------------------------------------------------------------------------- ''' count(...) S.count(sub[, start[, end]]) -> int Return the number of non-overlapping occurrences of substring sub in string S[start:end]. Optional arguments start and end are interpreted as in slice notation. ''' print(help(str.count)) a = 'askdfksghjkl' b = a.count('k') # 从下标为1到5计数‘s’的个数 print(b) # b = 2 ------------------------------------------------------------------------------------------- # 以 encoding 指定的编码格式编码字符串。errors参数可以指定不同的错误处理方案。 ''' encode(...) S.encode(encoding='utf-8', errors='strict') -> bytes Encode S using the codec registered for encoding. Default encoding is 'utf-8'. errors may be given to set a different error handling scheme. Default is 'strict' meaning that encoding errors raise a UnicodeEncodeError. Other possible values are 'ignore', 'replace' and 'xmlcharrefreplace' as well as any other name registered with codecs.register_error that can handle UnicodeEncodeErrors. ''' print(help(str.encode)) a = 'asdfsghjkl' b = a.encode('utf-8') print(b) # b = b'asdfsghjkl' ------------------------------------------------------------------------------------------- # 判断字符串是否以指定后缀结尾,如果以指定后缀结尾返回True,否则返回False。 # 可选参数"start"与"end"为检索字符串的开始与结束位置。 ''' endswith(...) S.endswith(suffix[, start[, end]]) -> bool suffix -- 该参数可以是一个字符串或者是一个元素。 start -- 字符串中的开始位置。 end -- 字符中结束位置。 Return True if S ends with the specified suffix, False otherwise. With optional start, test S beginning at that position. With optional end, stop comparing S at that position. suffix can also be a tuple of strings to try. ''' print(help(str.endswith)) a = 'asdfsghjk' b = a.endswith('k') c = a.endswith('j') d = a.endswith('a', 0, 1) e = a.endswith('a', 0, 2) print(b) # b = True print(c) # c = False print(d) # d = True print(e) # e = False ------------------------------------------------------------------------------------------- # 判断字符串是否以指定后缀结尾,如果以指定后缀结尾返回True,否则返回False。 # 可选参数"start"与"end"为检索字符串的开始与结束位置。 ''' expandtabs(...) S.expandtabs(tabsize=8) -> str Return a copy of S where all tab characters are expanded using spaces. If tabsize is not given, a tab size of 8 characters is assumed. ''' print(help(str.expandtabs)) a = 'asdfsghjk' b = a.endswith('k') c = a.endswith('j') d = a.endswith('a', 0, 1) e = a.endswith('a', 0, 2) print(b) # b = True print(c) # c = False print(d) # d = True print(e) # e = False ------------------------------------------------------------------------------------------- ''' find(...) 检测字符串中是否包含子字符串 str , 如果指定 beg(开始)和 end(结束)范围,则检查是否包含在指定范围内, 如果包含子字符串,则返回开始的索引值,否则返回-1。 S.find(sub[, start[, end]]) -> int Return the lowest index in S where substring sub is found, such that sub is contained within S[start:end]. Optional arguments start and end are interpreted as in slice notation. Return -1 on failure. ''' print(help(str.find)) a = 'asdfsghjk' b = a.find('d') c = a.find('f', 1, 4) # d = a.find('f', 1, 3) print(b) # 2 下标 print(c) # 2 从第一个字符到第三个字符中找,找到了则返回下标 print(d) # -1 ------------------------------------------------------------------------------------------- ''' format(...) # 格式换字符串输出(方法与%相似,但可以指定顺序) S.format(*args, **kwargs) -> str Return a formatted version of S, using substitutions from args and kwargs. The substitutions are identified by braces ('{' and '}'). None ''' print(help(str.format)) name = 'ske' fruit = 'apple' a = 'my name is {},I like {}'.format(name,fruit) b = 'my name is {1},I like {0}'.format(fruit,name) c = 'my name is {mingzi},I like {shuiguo}'.format(shuiguo=fruit,mingzi=name) print(a) # my name is ske,I like apple print(b) # my name is StivenWang,I like apple print(c) # my name is StivenWang,I like apple ------------------------------------------------------------------------------------------- ''' index(...) 检测字符串string中是否包含子字符串 str , 如果存在,则返回str在string中的索引值, 如果指定beg(开始)和 end(结束)范围,则检查是否包含在指定范围内, 该方法与 python find()方法一样,只不过如果str不在 string中会报一个异常(ValueError: substring not found)。 S.index(sub[, start[, end]]) -> int Like S.find() but raise ValueError when the substring is not found. None ''' # print(help(str.index)) a = "this is string example....wow!!!" b = "exam" #c = a.index(b) d = a.index(b, 20) #print(c) # 15 返回b字符串的第一个字符的索引值 print(d) # 报错 ------------------------------------------------------------------------------------------- ''' isalnum(...) 检测字符串是否由字母或数字组成 S.isalnum() -> bool Return True if all characters in S are alphanumeric and there is at least one character in S, False otherwise. None ''' print(help(str.isalnum)) a = "thisisstringexamplewow" b = "123" c = 'asdf1234' d = 'asdf!@@#' e = 'a = "this is string example wow"' print(a.isalnum()) # True 全部由字母构成 print(b.isalnum()) # True 全部由数字构成 print(c.isalnum()) # True 全部由字母或者数字构成 print(d.isalnum()) # False 有特殊字符 print(e.isalnum()) # False 有空格 ------------------------------------------------------------------------------------------- ''' isalpha(...) 检测字符串是否只由字母组成 S.isalpha() -> bool Return True if all characters in S are alphabetic and there is at least one character in S, False otherwise. None ''' print(help(str.isalpha)) a = "thisisstringexamplewow" b = "123" c = 'asdf1234' d = 'asdf!@@#' e = 'a = "this is string example wow"' print(a.isalpha()) # True 全部由字母构成 print(b.isalpha()) # False 有数字 print(c.isalpha()) # False 有数字 print(d.isalpha()) # False 没有字母 print(e.isalpha()) # False 有空格 -------------------------------------------------------------------------------------------
欢迎大家来到IT世界,在知识的湖畔探索吧!
篇幅有限无法放入所有demo,兴趣的读者可以私聊我或者加群:928233686领取我的所有笔记。
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